Optimal. Leaf size=111 \[ \frac{a b^2 \sin (c+d x)}{2 d}+\frac{(a+2 b) (a-b)^2 \log (\sin (c+d x)+1)}{4 d}-\frac{(a-2 b) (a+b)^2 \log (1-\sin (c+d x))}{4 d}+\frac{\sec ^2(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{2 d} \]
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Rubi [A] time = 0.134295, antiderivative size = 111, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {2668, 739, 774, 633, 31} \[ \frac{a b^2 \sin (c+d x)}{2 d}+\frac{(a+2 b) (a-b)^2 \log (\sin (c+d x)+1)}{4 d}-\frac{(a-2 b) (a+b)^2 \log (1-\sin (c+d x))}{4 d}+\frac{\sec ^2(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{2 d} \]
Antiderivative was successfully verified.
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Rule 2668
Rule 739
Rule 774
Rule 633
Rule 31
Rubi steps
\begin{align*} \int \sec ^3(c+d x) (a+b \sin (c+d x))^3 \, dx &=\frac{b^3 \operatorname{Subst}\left (\int \frac{(a+x)^3}{\left (b^2-x^2\right )^2} \, dx,x,b \sin (c+d x)\right )}{d}\\ &=\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{2 d}-\frac{b \operatorname{Subst}\left (\int \frac{(a+x) \left (-a^2+2 b^2+a x\right )}{b^2-x^2} \, dx,x,b \sin (c+d x)\right )}{2 d}\\ &=\frac{a b^2 \sin (c+d x)}{2 d}+\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{2 d}+\frac{b \operatorname{Subst}\left (\int \frac{-a b^2-a \left (-a^2+2 b^2\right )-2 b^2 x}{b^2-x^2} \, dx,x,b \sin (c+d x)\right )}{2 d}\\ &=\frac{a b^2 \sin (c+d x)}{2 d}+\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{2 d}+\frac{\left ((a-2 b) (a+b)^2\right ) \operatorname{Subst}\left (\int \frac{1}{b-x} \, dx,x,b \sin (c+d x)\right )}{4 d}-\frac{\left ((a-b)^2 (a+2 b)\right ) \operatorname{Subst}\left (\int \frac{1}{-b-x} \, dx,x,b \sin (c+d x)\right )}{4 d}\\ &=-\frac{(a-2 b) (a+b)^2 \log (1-\sin (c+d x))}{4 d}+\frac{(a-b)^2 (a+2 b) \log (1+\sin (c+d x))}{4 d}+\frac{a b^2 \sin (c+d x)}{2 d}+\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{2 d}\\ \end{align*}
Mathematica [A] time = 1.30535, size = 176, normalized size = 1.59 \[ \frac{\left (a^2-b^2\right ) \left ((a-2 b) (a+b)^2 \log (1-\sin (c+d x))-(a-b)^2 (a+2 b) \log (\sin (c+d x)+1)\right )+\tan ^2(c+d x) \left (4 a^2 b^3-8 a^4 b-2 a b^4 \sin (c+d x)+2 b^5\right )-a \tan (c+d x) \sec (c+d x) \left (4 a^2 b^2+2 a^4+b^4 \cos (2 (c+d x))-7 b^4\right )+2 a^4 b \sec ^2(c+d x)}{4 d \left (b^2-a^2\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.067, size = 154, normalized size = 1.4 \begin{align*}{\frac{{a}^{3}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{3\,{a}^{2}b}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{3\,a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{3\,a{b}^{2}\sin \left ( dx+c \right ) }{2\,d}}-{\frac{3\,a{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{{b}^{3} \left ( \tan \left ( dx+c \right ) \right ) ^{2}}{2\,d}}+{\frac{{b}^{3}\ln \left ( \cos \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.967185, size = 132, normalized size = 1.19 \begin{align*} \frac{{\left (a^{3} - 3 \, a b^{2} + 2 \, b^{3}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (a^{3} - 3 \, a b^{2} - 2 \, b^{3}\right )} \log \left (\sin \left (d x + c\right ) - 1\right ) - \frac{2 \,{\left (3 \, a^{2} b + b^{3} +{\left (a^{3} + 3 \, a b^{2}\right )} \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.36893, size = 273, normalized size = 2.46 \begin{align*} \frac{{\left (a^{3} - 3 \, a b^{2} + 2 \, b^{3}\right )} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (a^{3} - 3 \, a b^{2} - 2 \, b^{3}\right )} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 6 \, a^{2} b + 2 \, b^{3} + 2 \,{\left (a^{3} + 3 \, a b^{2}\right )} \sin \left (d x + c\right )}{4 \, d \cos \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16731, size = 154, normalized size = 1.39 \begin{align*} \frac{{\left (a^{3} - 3 \, a b^{2} + 2 \, b^{3}\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) -{\left (a^{3} - 3 \, a b^{2} - 2 \, b^{3}\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (b^{3} \sin \left (d x + c\right )^{2} + a^{3} \sin \left (d x + c\right ) + 3 \, a b^{2} \sin \left (d x + c\right ) + 3 \, a^{2} b\right )}}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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